bonjour dérivée f(x)= (x-2)² (x+1)

f(x)=(x-2)²(x+1)=(x²-4x+4)(x+1)=x³+x²-4x²-4x+4x+4=x³-3x²+4
f'(x)=3x²-6x

[tex]f(x) = (x-2)^2(x+1)\\ f(x) = (x^2-4x+4)(x+1)\\ f(x) =x^3-4x^2+4x+x^2-4x+4\\ f(x) = x^3-3x^2+4\\\\ f'(x)= 3x^2-6x[/tex]